Question # 1
What is the angle of refraction here,
shown in above fig?

Solution:

look at this formula
Refraction is described by Snell's law,
which states that for a given pair of media and a
wave with a single frequency, the ratio of
the sines of the angle of incidence θ1 and angle
of refraction θ2 is equivalent to the
ratio of phase velocities (v1 / v2) in the two media, or
equivalently, to the opposite ratio of the
indices of refraction (n2 / n1):

so from there
sinθ2=n2 (sinθ1/n1)
n1=1.00
there n2=1.52
θ1=30degree

question no 2 :

A radio transmitting station operating at
a frequency of 120MHz has two identical
antennas that radiate in phase. Antenna B
is 9.00m to the right of A. Consider point P
between the antennas and along the line
connecting them, a horizontal distance x to the
right of antenna A. For what values of x
will constructive interference occur at point P?

Solution:

Phy101
Assignment Solution spring 2012
As far i think .... look at this example please.... where the
same condition is given.
Two loudspeakers, A and B are driven by
the same amplifier and
emit sinusoidal waves in phase. Speaker B
is 2.00 m to the right of speaker A.
The frequency of the sound waves produced
by the loudspeakers is 206 Hz.
Consider point P between the speakers and
along the line connecting them,
a distance x to the right of speaker A.
Both speakers emit sound waves
that travel directly from the speaker to
point P.
b) For what values of x will constructive
interference occur at point P?

solution of example:
Assume speed of sound c = 343 m/s, then
wavelength lambda = c/f = 1.665 m and
lambda/4 = 0.41626 m. There are two
locations between the speakers where there is
interference. At the center the path
lengths are equal.
well wisher at http://www.vucybarien.com
For constructive interference you want a
pathlength difference equal to lambda multiplied
by an integer>=0. Then you have one
constructive point at the center and, using similar
logic as in A, two more at lambda/2 =
0.83252 m to either side. No more points can fit in
that space. The locations are at 1.03 
0.83252 and 1.03 + 0.83252
you can take hint from this example
just hint not perfect solution …….

question no 3
How is it possible to determine the
direction of the polarizing axis of a single polarizer?
Solution:
According to my opinion the vibration move
in one direction, by that we can determine
the direction of the polarizing axis of a
single polarize.

Remember me in your prays …..!!!!!!!
MEHRAN ALI SHAH
VIBD01

No comments:
Post a Comment